|
On the road to Astrophysics...
|
|
So anyone know how to calculate the electric field from a "thin" rod of length L at point P which is a perpendicular distance, y, from one end of the rod? The charge density ă (lambda) of the rod is given by ă=kx where k is a constant and x is the distance from the end point of the rod which P is perpendicular to, i.e. the charge density changes from one end of the rod to the other. Sorta looks like: P | |y | ============L x -the rod of length L is along the x axis shown as ============ -P is a perpendicular distance y from the end of the rod Calculate the E field at point P due to the rod of ă |
|
Re: On the road to Astrophysics...
Link |
by
on 2004-09-29 23:29:57 |
let the e-field at point p be denoted by Ep.Ep = ?çEsdswhere Es is some e-field due to the charge on the small section of the rod length ds. because this length is so small, we consider it a point charge. the value of this charge is ƒÉ*ds. by the definition of the e-field we know it's value to be: E = (Ke*Q) / R2in this case our Q is ƒÉ*ds and our R can be found using the Pythagorean theorem. you should have enough setup to generate and solve this integral, i hope. 
|