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Cryptography Challenge #37!
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on 2008-11-21 03:11:14 (edited 2010-11-17 10:31:08)
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This thread is for discussion of the Gendou.com Cryptography Challenge #37. Click the above link to view the challenge, get hints, and see the scoreboard. Please do NOT post spoilers! You may post your ideas and strategies, but no actual answers, ciphers, or code. 
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Re: Cryptography Challenge #37!
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on 2008-11-21 05:52:33 |
what does 2 adjacent numbers mean?  |
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Re: Cryptography Challenge #37!
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on 2008-11-21 06:35:34 |
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Ask yourself why you didn't try this before asking your question.
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Re: Cryptography Challenge #37!
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on 2008-11-21 07:20:31 |
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The hints really provided great info... Now its up to the brain to figure out the code.. Does the code have meaning?? Or is it just a list of random alphabets??
Tonight, We dine...IN HELL!!
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Re: Cryptography Challenge #37!
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on 2008-11-21 08:17:57 |
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well it says... "decode the secret message encoded below:" If it's a message, it probably isn't going to be random alphabets.  |
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Re: Cryptography Challenge #37!
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on 2008-11-21 09:11:05 |
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Im guessing for this coded message i should find a relation between the numbers, make out a possible equation, write down a list of numbers listing from 1-28+ and decode the code following A=1, B=2... n so on??
Tonight, We dine...IN HELL!!
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Re: Cryptography Challenge #37!
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on 2008-11-21 14:30:23 (edited 2008-11-21 14:31:16)
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Huh? I suppose I feel as confused trying to understand your question as you do trying to understand this challenge.
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Re: Cryptography Challenge #37!
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the math's not working out for me... so I must be misinterpreting the hints... random example: ... 6 3 4 5 1... Method A) The "two adjacent numbers" to 4 are 3 & 5, the two ON EITHER SIDE. Method B) The "two adjacent numbers" to 4 are 5 & 1, the two DIRECTLY AFTER. edit: do you HAVE to start at the beginning (Method B)? 15 is the addition of whatever letters 6 and 25 become?? which method is correct?! |
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Re: Cryptography Challenge #37!
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on 2008-11-21 19:52:55 (edited 2008-11-21 19:55:49)
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encode("FCDEA") = encode(6, 3, 4, 5, 1) = 6+3, 3+4, 4+5, 5+1, 1+6 = 9, 7, 9, 6, 7
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Re: Cryptography Challenge #37!
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ooooh, okay. thanks for the hint!   sammehhh for getting it first |
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Re: Cryptography Challenge #37!
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on 2008-11-21 21:16:18 |
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Re: Cryptography Challenge #37!
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on 2008-11-21 22:11:31 |
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AWESOME d00d!!! XD |
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Re: Cryptography Challenge #37!
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on 2008-11-21 22:16:07 |
Thanks for the hint^^  |
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Re: Cryptography Challenge #37!
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Actually, I just realized... did it go from #35 to #37? what happened to Crypto #36?? |
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Re: Cryptography Challenge #37!
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on 2008-11-22 00:01:01 |
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It's not ready yet. Under construction. I finished this one first, as it happened.
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Re: Cryptography Challenge #37!
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that must mean #36 is gonna be a hard one!  cant wait. |
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Re: Cryptography Challenge #37!
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on 2008-11-22 06:34:52 |
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*get confused at first* The hint really helpful! Thanks for it! ^^   |
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Re: Cryptography Challenge #37!
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on 2008-11-22 07:28:24 |
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Geez, im running outta solutions.... Oh well, this means i shud stop skipping classes but, my schooling days end in a few days... LoL Gendou, ur a master in physics??
Tonight, We dine...IN HELL!!
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Re: Cryptography Challenge #37!
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on 2008-11-22 16:03:02 |
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I have my bachelor's degree in computer science. Of course, as part of my degree I was required to take a year of physics. Since physics is my hobby, and I did audit a few advanced undergraduate courses.
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Re: Cryptography Challenge #37!
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on 2008-11-23 03:07:53 |
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I did it!!! my first time doing a challenge!!! woohoo! *do chicken dance* i'm not sure i got the right answer not tho... the answer is quite weird for me.. at least that what's think... thx dood.. |
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